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Rectifier Parts ?

Started by LowGear, September 27, 2013, 01:00:46 PM

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LowGear

Aloha,

I've got this dream to rectify around 5KW from a three phase generator to about 300 Volts DC for my SMA Grid Tie Inverter.

I've been watching these three phase units come through Ebay but they're the size of a pack of cigarettes.  I'm sorry but I just don't see these units lasting through the first tank of fuel.  Is this set of SCRs what I should be buying to build a reliable rectifier?

http://cgi.ebay.com/ws/eBayISAPI.dll?ViewItem&item=271286220946&ssPageName=ADME:B:SS:US:3160

Casey

Tom Reed

Ashwamegh 6/1 - ST5 @ just over 4000 hrs
ChangChi NM195
Witte BD Generator

Tom

Horsepoor


Thob

A little bit about rectifier diodes:

In general, you need a voltage rating of at least 2x the DC output voltage.  In practice, you need a considerable safety margin, something like 25%.  This allows for the voltage to be higher under no load, and for spikes, etc.  So for 300 volt DC output, you would want at least 750 volt diodes.  1000V would be better.

For the current rating, you need it to be at least as much as your average DC current.  Again, a good safety factor is in order.  5KW / 300V = 16.7A, so something like 20A diodes would be the minimum.

Always get two of them - you should have a spare!

Unless you're using some kind of fancy control circuit, you don't want the SCRs in your link.

For 300V DC out, you'll need about 215V AC in.

Somebody better check my math -
Witte 98RC Gas burner - Kubota D600 w/ST7.5KW head.
I'm not afraid to take anything apart.
I am sometimes afraid I'm not going to get it back together.

mike90045

For single phase, you need 4 diodes for a full wave rectifier, unless you have a center tap winding, and then you can use just 2 diodes.

Diodes generate heat, and they have to be kept cool, so figure they drop 1.5V across them at whatever amps, and those are the watts you have to dissipate.   Schottky diodes have less voltage drop, and therefore dissipate less power.  And generally, one lead of the diode is electrically attached to the heat sink.  volts * amps = watts.   1.5V * 7A = 10.5 watts, per diode

Diode Bridge Packs generally isolate the electrical from the heat sink, and you just need 1 bolt to a heat sink to keep all the diodes cool.

LowGear